Delayed start of a thread in C++ 11

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std::thread‘s default constructor instantiates a std::thread without starting or representing any actual thread.

std::thread t;

The assignment operator moves the state of a thread object, and sets the assigned-from thread object to its default-initialized state:

t = std::thread(/* new thread code goes here */);

This first constructs a temporary thread object representing a new thread, transfers the new thread representation into the existing thread object that has a default state, and sets the temporary thread object’s state to the default state that does not represent any running thread. Then the temporary thread object is destroyed, doing nothing.

Here’s an example:

#include <iostream>
#include <thread>

void thread_func(const int i) {
    std::cout << "hello from thread: " << i << std::endl;
}

int main() {
    std::thread t;
    std::cout << "t exists" << std::endl;

    t = std::thread{ thread_func, 7 };
    t.join();

    std::cout << "done!" << std::endl;
}

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