friend declaration declares a non-template function [duplicate]

by

It sounds like you want to change: 

friend ostream& operator << (ostream& out, const Base<T>& e);

To:

template<class T>
friend ostream& operator << (ostream& out, const Base<T>& e);

More Related Contents:

  1. overloading friend operator
  2. C++ template friend operator overloading
  3. explicit specialization of template class member function
  4. Template specialization of particular members?
  5. How to declare a templated struct/class as a friend?
  6. c++ template partial specialization member function [duplicate]
  7. Selecting a member function using different enable_if conditions
  8. declare template friend function of template class
  9. Template specialization of a single method from a templated class
  10. Making a template parameter a friend?
  11. ‘friend’ functions and
  12. How do we declare a friend function with a class template into .h file and define them into a .cpp file (not all in one header file)?
  13. static member initialization for specialized template class
  14. Overload operators as member function or non-member (friend) function?
  15. Default template parameter partial specialization
  16. Implicit conversion when overloading operators for template classes
  17. Specializing function template for reference types
  18. Overloading operator
  19. Specializing a template on a lambda in C++0x
  20. Default template argument and partial specialization
  21. Template specialization based on inherit class
  22. How to detect whether there is a specific member variable in class?
  23. Why not infer template parameter from constructor?
  24. Explicit template instantiation – when is it used?
  25. C++ Static member initialization (template fun inside)
  26. Access friend function defined in class
  27. Template function as a template argument
  28. What does this variadic template code do?
  29. How to overload unary minus operator in C++?
  30. How to write `is_complete` template?

Leave a Comment