This has nothing to do with functools.partial
, really. You are essentially calling your function like this:
f(1, x=3)
Python first fulfils the positional arguments, and your first argument is x
. Then the keyword arguments are applied, and you again supplied x
.
functools.partial()
has no means to detect that you already supplied the first positional argument as a keyword argument instead. It will not augment your call by replacing the positional argument with a y=
keyword argument.
When mixing positional and keyword arguments, you must take care not to use the same argument twice.