Getting the caller function name inside another function in Python? [duplicate]

You can use the inspect module to get the info you want. Its stack method returns a list of frame records.

• For Python 2 each frame record is a list. The third element in each record is the caller name. What you want is this:

  >>> import inspect
  >>> def f():
  ...     print inspect.stack()[1][3]
  ...
  >>> def g():
  ...     f()
  ...
  >>> g()
  g
  

• For Python 3.5+, each frame record is a named tuple so you need to replace

  print inspect.stack()[1][3]
  

  with

  print(inspect.stack()[1].function)
  

  on the above code.