Grab a segment of an array in Java without creating a new array on heap

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Disclaimer: This answer does not conform to the constraints of the question:

I don’t want to have to create a new byte array in the heap memory just to do that.

(Honestly, I feel my answer is worthy of deletion. The answer by @unique72 is correct. Imma let this edit sit for a bit and then I shall delete this answer.)

I don’t know of a way to do this directly with arrays without additional heap allocation, but the other answers using a sub-list wrapper have additional allocation for the wrapper only – but not the array – which would be useful in the case of a large array.

That said, if one is looking for brevity, the utility method Arrays.copyOfRange() was introduced in Java 6 (late 2006?):

byte [] a = new byte [] {0, 1, 2, 3, 4, 5, 6, 7};

// get a[4], a[5]

byte [] subArray = Arrays.copyOfRange(a, 4, 6);

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