How do I compare two Integers? [duplicate]

This is what the equals method does:

public boolean equals(Object obj) {
    if (obj instanceof Integer) {
        return value == ((Integer)obj).intValue();
    }
    return false;
}

As you can see, there’s no hash code calculation, but there are a few other operations taking place there. Although x.intValue() == y.intValue() might be slightly faster, you’re getting into micro-optimization territory there. Plus the compiler might optimize the equals() call anyway, though I don’t know that for certain.

I generally would use the primitive int, but if I had to use Integer, I would stick with equals().

Leave a Comment