String test = "{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";
System.out.println(StringEscapeUtils.unescapeJava(test));
This might help you.
More Related Contents:
- How to use Jackson to deserialise an array of objects
- How to tell Jackson to ignore a field during serialization if its value is null?
- Java 8 LocalDate Jackson format
- When is the @JsonProperty property used and what is it used for?
- Jackson – Deserialize using generic class
- Jackson with JSON: Unrecognized field, not marked as ignorable
- How to convert a JSON string to a Map with Jackson JSON
- Different names of JSON property during serialization and deserialization
- Date format Mapping to JSON Jackson
- Deserialize JSON with Jackson into Polymorphic Types – A Complete Example is giving me a compile error
- JsonMappingException: No suitable constructor found for type [simple type, class ]: can not instantiate from JSON object
- Jackson serialization: ignore empty values (or null)
- Parsing JSON in Java without knowing JSON format
- Jackson JSON Deserialization with Root Element
- Jackson overcoming underscores in favor of camel-case
- Generics with Spring RESTTemplate
- Jackson Change JsonIgnore Dynamically
- Query a JSONObject in java
- How to modify JsonNode in Java?
- How to create a custom deserializer in Jackson for a generic type?
- JPA Transient Annotation and JSON
- How to convert XML to JSON using only Jackson?
- How to enforce ACCEPT_SINGLE_VALUE_AS_ARRAY in jackson’s deserialization process using annotation
- spring mvc not returning json content – error 406
- Removing JSON elements with jackson
- Jackson – Required property?
- Deserializing non-string map keys with Jackson
- How to annotate enum fields for deserialization using Jackson json
- How to customise Jackson in Spring Boot 1.4
- How do I parametrize response parsing in Java?