How to escape a square bracket for Pattern compilation?

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For some reason, the above answer didn’t work for me. For those like me who come after, here is what I found.

I was expecting a single backslash to escape the bracket, however, you must use two if you have the pattern stored in a string. The first backslash escapes the second one into the string, so that what regex sees is \]. Since regex just sees one backslash, it uses it to escape the square bracket.

\\]

In regex, that will match a single closing square bracket.

If you’re trying to match a newline, for example though, you’d only use a single backslash. You’re using the string escape pattern to insert a newline character into the string. Regex doesn’t see \n – it sees the newline character, and matches that. You need two backslashes because it’s not a string escape sequence, it’s a regex escape sequence.

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