Remove your capturing group:
ip = re.findall( r'[0-9]+(?:\.[0-9]+){3}', s )
Result:
['165.91.15.131']
Notes:
- If you are parsing HTML it might be a good idea to look at BeautifulSoup.
- Your regular expression matches some invalid IP addresses such as
0.00.999.9999
. This isn’t necessarily a problem, but you should be aware of it and possibly handle this situation. You could change the+
to{1,3}
for a partial fix without making the regular expression overly complex.