How to extract string following a pattern with grep, regex or perl [duplicate]

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Since you need to match content without including it in the result (must
match name=" but it’s not part of the desired result) some form of
zero-width matching or group capturing is required. This can be done
easily with the following tools:

Perl

With Perl you could use the n option to loop line by line and print
the content of a capturing group if it matches:

perl -ne 'print "$1\n" if /name="(.*?)"https://stackoverflow.com/" filename

GNU grep

If you have an improved version of grep, such as GNU grep, you may have
the -P option available. This option will enable Perl-like regex,
allowing you to use \K which is a shorthand lookbehind. It will reset
the match position, so anything before it is zero-width.

grep -Po 'name="\K.*?(?=")' filename

The o option makes grep print only the matched text, instead of the
whole line.

Vim – Text Editor

Another way is to use a text editor directly. With Vim, one of the
various ways of accomplishing this would be to delete lines without
name= and then extract the content from the resulting lines:

:v/.*name="\v([^"]+).*/d|%s//\1

Standard grep

If you don’t have access to these tools, for some reason, something
similar could be achieved with standard grep. However, without the look
around it will require some cleanup later:

grep -o 'name="[^"]*"' filename

A note about saving results

In all of the commands above the results will be sent to stdout. It’s
important to remember that you can always save them by piping it to a
file by appending:

> result

to the end of the command.

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