How to iterate over arguments in a Bash script

by

Use "$@" to represent all the arguments:

for var in "$@"
do
    echo "$var"
done

This will iterate over each argument and print it out on a separate line. $@ behaves like $* except that when quoted the arguments are broken up properly if there are spaces in them:

sh test.sh 1 2 '3 4'
1
2
3 4

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