How to reliably open a file in the same directory as the currently running script

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I always use:

__location__ = os.path.realpath(
    os.path.join(os.getcwd(), os.path.dirname(__file__)))

The join() call prepends the current working directory, but the documentation says that if some path is absolute, all other paths left of it are dropped. Therefore, getcwd() is dropped when dirname(__file__) returns an absolute path.

Also, the realpath call resolves symbolic links if any are found. This avoids troubles when deploying with setuptools on Linux systems (scripts are symlinked to /usr/bin/ — at least on Debian).

You may the use the following to open up files in the same folder:

f = open(os.path.join(__location__, 'bundled-resource.jpg'))
# ...

I use this to bundle resources with several Django application on both Windows and Linux and it works like a charm!

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