How to transform a tuple to a string of values without comma and parentheses

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Use str.join():

>>> mystring = ' '.join(map(str, (34.2424, -64.2344, 76.3534, 45.2344)))
>>> print mystring
34.2424 -64.2344 76.3534 45.2344

You’ll have to use map here (which converts all the items in the tuple to strings) because otherwise you will get a TypeError.

A bit of clarification on the map() function:

map(str, (34.2424, -64.2344, 76.3534, 45.2344) is equivalent to [str(i) for i in (34.2424, -64.2344, 76.3534, 45.2344)].

It’s a tiny bit faster than using a list comprehension:

$ python -m timeit "map(str, (34.2424, -64.2344, 76.3534, 45.2344))"
1000000 loops, best of 3: 1.93 usec per loop
$ python -m timeit "[str(i) for i in (34.2424, -64.2344, 76.3534, 45.2344)]"
100000 loops, best of 3: 2.02 usec per loop

As shown in the comments to this answer, str.join() can take a generator instead of a list. Normally, this would be faster, but in this case, it is slower.

If I were to do:

' '.join(itertools.imap(str, (34.2424, -64.2344, 76.3534, 45.2344)))

It would be slower than using map(). The difference is that imap() returns a generator, while map() returns a list (in python 3 it returns a generator)

If I were to do:

''.join(str(i) for i in (34.2424, -64.2344, 76.3534, 45.2344))

It would be slower than putting brackets around the list comprehension, because of reasons explained here.

In your (OP’s) case, either option does not really matter, as performance doesn’t seem like a huge deal here. But if you are ever dealing with large tuples of floats/integers, then now you know what to use for maximum efficiency :).

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