How to use re to find consecutive, repeated chars

by

((\w)\2{2,}) matches 3 or more consecutive characters:

In [71]: import re
In [72]: s = r'http://www.google.com/search=ooo-jjjj'
In [73]: re.findall(r'((\w)\2{2,})', s)
Out[73]: [('www', 'w'), ('ooo', 'o'), ('jjjj', 'j')]

In [78]: [match[0] for match in re.findall(r'((\w)\2{2,})', s)]
Out[78]: ['www', 'ooo', 'jjjj']

(\w) matches any alphanumeric character.

((\w)\2) matches any alphanumeric character followed by the same character, since \2 matches the contents of group number 2.
Since I nested the parentheses, group number 2 refers to the character matched by \w.

Then putting it all together,
((\w)\2{2,}) matches any alphanumeric character, followed by the same character repeated 2 or more additional times.

In total, that means the regex require the character to be repeated 3 or more times.

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