If you know the size of type, you could do something like:
uint i = 17;
uint j = i << 1 | i >> 31;
… which would perform a circular shift of a 32 bit value.
As a generalization to circular shift left n bits, on a b bit variable:
/*some unsigned numeric type*/ input = 17;
var result = input << n | input >> (b - n);
@The comment, it appears that C# does treat the high bit of signed values differently. I found some info on this here. I also changed the example to use a uint.