The syntax you’re looking for:
lambda x: True if x % 2 == 0 else False
But you can’t use print
or raise
in a lambda.
More Related Contents:
- Does Python have a ternary conditional operator?
- What do lambda function closures capture?
- How are lambdas useful? [closed]
- How to understand closure in a lambda?
- Finding the average of a list
- Is it pythonic: naming lambdas
- How do I create a list of lambdas (in a list comprehension/for loop)?
- Syntax behind sorted(key=lambda: …)
- python max function using ‘key’ and lambda expression
- Tkinter lambda function
- Can Python pickle lambda functions?
- Can a lambda function call itself recursively in Python?
- Which is more preferable to use: lambda functions or nested functions (‘def’)?
- Assignment inside lambda expression in Python
- What is key=lambda
- List comprehension and lambdas in Python [duplicate]
- How can I use a conditional expression (expression with if and else) in a list comprehension? [duplicate]
- lambda function don’t closure the parameter in Python? [duplicate]
- Python pandas – filter rows after groupby
- Python lambda doesn’t remember argument in for loop [duplicate]
- Lifetime of object in lambda connected to pyqtSignal
- Check if two Python functions are equal
- Use value of variable in lambda expression [duplicate]
- Python lambda does not accept tuple argument [duplicate]
- Why do parentheses in a lambda function cause syntax error on Python 3? [duplicate]
- Why use lambda functions?
- How to use await in a python lambda
- Dictionary With Lambda Values Updates All Entries
- PyQt5 button lambda variable becomes boolean [duplicate]
- Python one-line “for” expression [duplicate]