Java BigDecimal precision problems

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What you actually want is

new BigDecimal("0.1")
 .add(new BigDecimal("0.1"))
 .add(new BigDecimal("0.1"));

The new BigDecimal(double) constructor gets all the imprecision of the double, so by the time you’ve said 0.1, you’ve already introduced the rounding error. Using the String constructor avoids the rounding error associated with going via the double.

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