Java Jar file: use resource errors: URI is not hierarchical

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You cannot do this

File src = new File(resourceUrl.toURI()); //ERROR HERE

it is not a file!
When you run from the ide you don’t have any error, because you don’t run a jar file. In the IDE classes and resources are extracted on the file system.

But you can open an InputStream in this way:

InputStream in = Model.class.getClassLoader().getResourceAsStream("/data.sav");

Remove "/resource". Generally the IDEs separates on file system classes and resources. But when the jar is created they are put all together. So the folder level "/resource" is used only for classes and resources separation.

When you get a resource from classloader you have to specify the path that the resource has inside the jar, that is the real package hierarchy.

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