You get this exception because your url
variable is null on this line:
String url = WebViewSample.class.getResource("/map.html").toExternalForm();
You have several options with getResource()
:
If the resource is the same directory as the class, then you can use
String url = WebViewSample.class.getResource("map.html").toExternalForm();
Using beginning slash(“https://stackoverflow.com/”) means relative path to the project root.:
In your particular case, if the resource is stored in the webviewsample
package, you can get the resource as:
String url = WebViewSample.class.getResource("/webviewsample/map.html").toExternalForm();
Using a beginning dot-slash(“./”) means relative path to path of the class:
Imagine that you rclass is stored in package webviewsample
, and your resource (map.html
) is stored in a subdirectory res
. You can use this command to get the URL:
String url = WebViewSample.class.getResource("./res/map.html").toExternalForm();
Based on this, if your resource is in the same directory with your class, then:
String url = WebViewSample.class.getResource("map.html").toExternalForm();
and
String url = WebViewSample.class.getResource("./map.html").toExternalForm();
are equivalent.
For further reading you can check the documentation of getResource()
.