Linear regression analysis with string/categorical features (variables)?

Yes, you will have to convert everything to numbers. That requires thinking about what these attributes represent.

Usually there are three possibilities:

  1. One-Hot encoding for categorical data
  2. Arbitrary numbers for ordinal data
  3. Use something like group means for categorical data (e. g. mean prices for city districts).

You have to be carefull to not infuse information you do not have in the application case.

One hot encoding

If you have categorical data, you can create dummy variables with 0/1 values for each possible value.

E. g.

idx color
0   blue
1   green
2   green
3   red

to

idx blue green red
0   1    0     0
1   0    1     0
2   0    1     0
3   0    0     1

This can easily be done with pandas:

import pandas as pd

data = pd.DataFrame({'color': ['blue', 'green', 'green', 'red']})
print(pd.get_dummies(data))

will result in:

   color_blue  color_green  color_red
0           1            0          0
1           0            1          0
2           0            1          0
3           0            0          1

Numbers for ordinal data

Create a mapping of your sortable categories, e. g.
old < renovated < new → 0, 1, 2

This is also possible with pandas:

data = pd.DataFrame({'q': ['old', 'new', 'new', 'ren']})
data['q'] = data['q'].astype('category')
data['q'] = data['q'].cat.reorder_categories(['old', 'ren', 'new'], ordered=True)
data['q'] = data['q'].cat.codes
print(data['q'])

Result:

0    0
1    2
2    2
3    1
Name: q, dtype: int8

Using categorical data for groupby operations

You could use the mean for each category over past (known events).

Say you have a DataFrame with the last known mean prices for cities:

prices = pd.DataFrame({
    'city': ['A', 'A', 'A', 'B', 'B', 'C'],
    'price': [1, 1, 1, 2, 2, 3],
})
mean_price = prices.groupby('city').mean()
data = pd.DataFrame({'city': ['A', 'B', 'C', 'A', 'B', 'A']})

print(data.merge(mean_price, on='city', how='left'))

Result:

  city  price
0    A      1
1    B      2
2    C      3
3    A      1
4    B      2
5    A      1

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