Mongo order by length of array

I thought you might be able to use $size, but that’s only to find arrays of a certain size, not ordering.

From the mongo documentation:
http://www.mongodb.org/display/DOCS/Advanced+Queries#AdvancedQueries-%24size

You cannot use $size to find a range of sizes (for example: arrays with more than 1 element). If you need to query for a range, create an extra size field that you increment when you add elements. Indexes cannot be used for the $size portion of a query, although if other query expressions are included indexes may be used to search for matches on that portion of the query expression.

Looks like you can probably fairly easily do this with the new aggregation framework, edit: which isn’t out yet.
http://www.mongodb.org/display/DOCS/Aggregation+Framework

Update Now the Aggregation Framework is out…

> db.test.aggregate([
  {$unwind: "$answers"}, 
  {$group: {_id:"$_id", answers: {$push:"$answers"}, size: {$sum:1}}}, 
  {$sort:{size:1}}]);
{
"result" : [
    {
        "_id" : ObjectId("5053b4547d820880c3469365"),
        "answers" : [
            {
                "content" : "answer1"
            },
            {
                "content" : "2nd answer"
            }
        ],
        "size" : 2
    },
    {
        "_id" : ObjectId("5053b46d7d820880c3469366"),
        "answers" : [
            {
                "content" : "answer1"
            },
            {
                "content" : "2nd answer"
            },
            {
                "content" : "The third answer"
            }
        ],
        "size" : 3
    }
  ],
  "ok" : 1
}

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