MySQL doesn’t have recursive functionality, so you’re left with using the NUMBERS table trick –
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Create a table that only holds incrementing numbers – easy to do using an auto_increment:
DROP TABLE IF EXISTS `example`.`numbers`; CREATE TABLE `example`.`numbers` ( `id` int(10) unsigned NOT NULL auto_increment, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1;
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Populate the table using:
INSERT INTO `example`.`numbers` ( `id` ) VALUES ( NULL )
…for as many values as you need.
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Use DATE_ADD to construct a list of dates, increasing the days based on the NUMBERS.id value. Replace “2010-06-06” and “2010-06-14” with your respective start and end dates (but use the same format, YYYY-MM-DD) –
SELECT `x`.* FROM (SELECT DATE_ADD('2010-06-06', INTERVAL `n`.`id` - 1 DAY) FROM `numbers` `n` WHERE DATE_ADD('2010-06-06', INTERVAL `n`.`id` -1 DAY) <= '2010-06-14' ) x
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LEFT JOIN onto your table of data based on the time portion:
SELECT `x`.`ts` AS `timestamp`, COALESCE(`y`.`score`, 0) AS `cnt` FROM (SELECT DATE_FORMAT(DATE_ADD('2010-06-06', INTERVAL `n`.`id` - 1 DAY), '%m/%d/%Y') AS `ts` FROM `numbers` `n` WHERE DATE_ADD('2010-06-06', INTERVAL `n`.`id` - 1 DAY) <= '2010-06-14') x LEFT JOIN TABLE `y` ON STR_TO_DATE(`y`.`date`, '%d.%m.%Y') = `x`.`ts`
If you want to maintain the date format, use the DATE_FORMAT function:
DATE_FORMAT(`x`.`ts`, '%d.%m.%Y') AS `timestamp`