Nested List and count()

by 
>>> L = [[1, 2, 3], [1, 1, 1]]
>>> sum(x.count(1) for x in L)
4

More Related Contents:

  1. How to iterate through two lists in parallel?
  2. Transpose/Unzip Function (inverse of zip)?
  3. Iterating over every two elements in a list [duplicate]
  4. Are lists thread-safe?
  5. Python List vs. Array – when to use?
  6. How can I iterate through two lists in parallel?
  7. Getting a list of values from a list of dicts
  8. Pairs from single list
  9. Splitting a list based on a delimiter word
  10. What is the most pythonic way to pop a random element from a list?
  11. Naming conflict with built-in function
  12. Interleaving Lists in Python [duplicate]
  13. Does a slicing operation give me a deep or shallow copy?
  14. Confused about __str__ on list in Python [duplicate]
  15. join two lists of dictionaries on a single key
  16. Print LIST of unicode chars without escape characters
  17. Confusing […] List in Python: What is it?
  18. How to delete an item in a list if it exists?
  19. What is time complexity of a list to set conversion?
  20. Flattening a list recursively [duplicate]
  21. remove None value from a list without removing the 0 value
  22. Filtering a list based on a list of booleans
  23. Creating an empty list in Python
  24. Python: Remove Duplicate Items from Nested list
  25. Changing one dict changes all dicts in a list of dicts [duplicate]
  26. Python string.join(list) on object array rather than string array
  27. How to sort multidimensional array by column?
  28. sum each value in a list of tuples
  29. How do I send list of dictionary as Body parameter together with Files in FastAPI?
  30. deque.popleft() and list.pop(0). Is there performance difference?

Leave a Comment