pointer to array c++

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The parenthesis are superfluous in your example. The pointer doesn’t care whether there’s an array involved – it only knows that its pointing to an int

  int g[] = {9,8};
  int (*j) = g;

could also be rewritten as 

  int g[] = {9,8};
  int *j = g;

which could also be rewritten as

  int g[] = {9,8};
  int *j = &g[0];

a pointer-to-an-array would look like

  int g[] = {9,8};
  int (*j)[2] = &g;

  //Dereference 'j' and access array element zero
  int n = (*j)[0];

There’s a good read on pointer declarations (and how to grok them) at this link here: http://www.codeproject.com/Articles/7042/How-to-interpret-complex-C-C-declarations

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