import re
s="abcd2343 abw34324 abc3243-23A"
re.split('(\d+)',s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A']
Or, if you want to split on the first occurrence of a digit:
re.findall('\d*\D+',s)
> ['abcd', '2343 abw', '34324 abc', '3243-', '23A']
\d+
matches 1-or-more digits.\d*\D+
matches 0-or-more digits followed by 1-or-more non-digits.\d+|\D+
matches 1-or-more digits or 1-or-more non-digits.
Consult the docs for more about Python’s regex syntax.
re.split(pat, s)
will split the string s
using pat
as the delimiter. If pat
begins and ends with parentheses (so as to be a “capturing group”), then re.split
will return the substrings matched by pat
as well. For instance, compare:
re.split('\d+', s)
> ['abcd', ' abw', ' abc', '-', 'A'] # <-- just the non-matching parts
re.split('(\d+)', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A'] # <-- both the non-matching parts and the captured groups
In contrast, re.findall(pat, s)
returns only the parts of s
that match pat
:
re.findall('\d+', s)
> ['2343', '34324', '3243', '23']
Thus, if s
ends with a digit, you could avoid ending with an empty string by using re.findall('\d+|\D+', s)
instead of re.split('(\d+)', s)
:
s="abcd2343 abw34324 abc3243-23A 123"
re.split('(\d+)', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123', '']
re.findall('\d+|\D+', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123']