Python ElementTree module: How to ignore the namespace of XML files to locate matching element when using the method “find”, “findall”

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Instead of modifying the XML document itself, it’s best to parse it and then modify the tags in the result. This way you can handle multiple namespaces and namespace aliases:

from io import StringIO  # for Python 2 import from StringIO instead
import xml.etree.ElementTree as ET

# instead of ET.fromstring(xml)
it = ET.iterparse(StringIO(xml))
for _, el in it:
    prefix, has_namespace, postfix = el.tag.partition('}')
    if has_namespace:
        el.tag = postfix  # strip all namespaces
root = it.root

This is based on the discussion here:
http://bugs.python.org/issue18304

Update: rpartition instead of partition makes sure you get the tag name in postfix even if there is no namespace. Thus you could condense it:

for _, el in it:
    _, _, el.tag = el.tag.rpartition('}') # strip ns

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