Python Window Activation

You can use the win32gui module to do that. First you need to get a valid handle on your window. You can use the win32gui.FindWindow if you know the window class name or the exact title. If not, you can enumerate the windows with the win32gui.EnumWindows and try to find the right one.

Once you have the handle, you can call the win32gui.SetForegroundWindow with the handle. It will activate the window and will be ready for getting your keystrokes.

See an example below. I hope it helps

import win32gui
import re


class WindowMgr:
    """Encapsulates some calls to the winapi for window management"""

    def __init__ (self):
        """Constructor"""
        self._handle = None

    def find_window(self, class_name, window_name=None):
        """find a window by its class_name"""
        self._handle = win32gui.FindWindow(class_name, window_name)

    def _window_enum_callback(self, hwnd, wildcard):
        """Pass to win32gui.EnumWindows() to check all the opened windows"""
        if re.match(wildcard, str(win32gui.GetWindowText(hwnd))) is not None:
            self._handle = hwnd

    def find_window_wildcard(self, wildcard):
        """find a window whose title matches the wildcard regex"""
        self._handle = None
        win32gui.EnumWindows(self._window_enum_callback, wildcard)

    def set_foreground(self):
        """put the window in the foreground"""
        win32gui.SetForegroundWindow(self._handle)


w = WindowMgr()
w.find_window_wildcard(".*Hello.*")
w.set_foreground()