UPDATE: It fails “with two ff before oo” as @Ciantic pointed out in the comments.
^(f(o[^o]|[^o])|[^f])*$
NOTE: It is much much easier just to negate a match on the client side instead of using the above regex.
The regex assumes that each line ends with a newline char if it is not then see C++’s and grep’s regexs.
Sample programs in Perl, Python, C++, and grep
all give the same output.
-
#!/usr/bin/perl -wn print if /^(f(o[^o]|[^o])|[^f])*$/;
-
#!/usr/bin/env python import fileinput, re, sys from itertools import ifilter re_not_foo = re.compile(r"^(f(o[^o]|[^o])|[^f])*$") for line in ifilter(re_not_foo.match, fileinput.input()): sys.stdout.write(line)
-
c++
#include <iostream> #include <string> #include <boost/regex.hpp> int main() { boost::regex re("^(f(o([^o]|$)|([^o]|$))|[^f])*$"); //NOTE: "|$"s are there due to `getline()` strips newline char std::string line; while (std::getline(std::cin, line)) if (boost::regex_match(line, re)) std::cout << line << std::endl; }
-
$ grep "^\(f\(o\([^o]\|$\)\|\([^o]\|$\)\)\|[^f]\)*$" in.txt
Sample file:
foo
'foo'
abdfoode
abdfode
abdfde
abcde
f
fo
foo
fooo
ofooa
ofo
ofoo
Output:
abdfode
abdfde
abcde
f
fo
ofo