Returning overlapping regular expressions

by

Sure, match an empty string and place a look-ahead after it that captures /.* in a capturing group:

Matcher m = Pattern.compile("(?=(/.*))").matcher("/abc/def/ghi");
while(m.find()) {
  System.out.println(m.group(1));
}

would print:

/abc/def/ghi
/def/ghi
/ghi

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