If you want to get the last page number of the above the link for proceeding, which is 499 you can use either Selenium or Beautifulsoup as follows :
Selenium :
from selenium import webdriver
driver = webdriver.Firefox(executable_path=r'C:\Utility\BrowserDrivers\geckodriver.exe')
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
driver.get(url)
element = driver.find_element_by_xpath("//div[@class="row pagination"]//p/span[contains(.,'Reviews on Reliance Jio')]")
driver.execute_script("return arguments[0].scrollIntoView(true);", element)
print(driver.find_element_by_xpath("//ul[@class="pagination table"]/li/ul[@class="pages table"]//li[last()]/a").get_attribute("innerHTML"))
driver.quit()
Console Output :
499
Beautifulsoup :
import bs4
from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
uClient = uReq(url)
page_html = uClient.read()
uClient.close()
page_soup = soup(page_html, "html.parser")
container = page_soup.find("ul",{"class":"pages table"})
all_li = container.findAll("li")
last_div = None
for last_div in all_li:pass
if last_div:
content = last_div.getText()
print(content)
Console Output :
499