There are 2 basic ways:
var arr = [{name:"ABC"},{name:"BAC"},{name:"abc"},{name:"bac"}];
arr.sort(function(a,b){
var alc = a.name.toLowerCase(), blc = b.name.toLowerCase();
return alc > blc ? 1 : alc < blc ? -1 : 0;
});
or
arr.sort(function(a,b){
return a.name.toLowerCase().localeCompare(b.name.toLowerCase());
});
Be aware that the 2nd version ignore diacritics, so a
and à
will be sorted as the same letter.
Now the problem with both these ways is that they will not sort uppercase ABC
before lowercase abc
, since it will treat them as the same.
To fix that, you will have to do it like this:
arr.sort(function(a,b){
var alc = a.name.toLowerCase(), blc = b.name.toLowerCase();
return alc > blc ? 1 : alc < blc ? -1 : a.name > b.name ? 1 : a.name < b.name ? -1 : 0;
});
Again here you could choose to use localeCompare
instead if you don’t want diacritics to affect the sorting like this:
arr.sort(function(a,b){
var lccomp = a.name.toLowerCase().localeCompare(b.name.toLowerCase());
return lccomp ? lccomp : a.name > b.name ? 1 : a.name < b.name ? -1 : 0;
});
You can read more about sort here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort