Sorting on a custom order

by

Improved version of Cerbrus’ code:

var ordering = {}, // map for efficient lookup of sortIndex
    sortOrder = ['fruit','candy','vegetable'];
for (var i=0; i<sortOrder.length; i++)
    ordering[sortOrder[i]] = i;

somethingToSort.sort( function(a, b) {
    return (ordering[a.type] - ordering[b.type]) || a.name.localeCompare(b.name);
});

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