Swift filter dictionary error: Cannot assign a value of type ‘[(_, _)]’ to a value of type ‘[_ : _]’

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This has been fixed in Swift 4

let data = ["a": 0, "b": 42]
let filtered = data.filter { $0.value > 10 }
print(filtered) // ["b": 42]

In Swift 4, a filtered dictionary returns a dictionary.

Original answer for Swift 2 and 3

The problem is that data is a dictionary but the result of filter is an array, so the error message says that you can’t assign the result of the latter to the former.

You could just create a new variable/constant for your resulting array:

let data: [String: String] = [:]
let filtered = data.filter { $0.1 == "Test" }

Here filtered is an array of tuples: [(String, String)].

Once filtered, you can recreate a new dictionary if this is what you need:

var newData = [String:String]()
for result in filtered {
    newData[result.0] = result.1
}

If you decide not to use filter you could mutate your original dictionary or a copy of it:

var data = ["a":"Test", "b":"nope"]
for (key, value) in data {
    if value != "Test" {
        data.removeValueForKey(key)
    }
}
print(data) // ["a": "Test"]

Note: in Swift 3, removeValueForKey has been renamed removeValue(forKey:), so in this example it becomes data.removeValue(forKey: key).

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