You need to add an app.manifest. Change the requestedExecutionLevel from asInvoker to requireAdministrator. You can create a new manifest by using the add file dialog, change it to require administrator. Make sure that your project settings are set to use that manifest as well. This will allow you to simply double click the application and … Read more
You can programmatically set the “Run this program as an administrator” flag (the option you find in the Compatibility tab of an EXE’s properties), by setting a simple registry key. You need to create a string value (REG_SZ) under one of these keys (if you want the setting to be per user or per machine, … Read more
You may not be able to do it directly. From the documentation of list_display ManyToManyField fields aren’t supported, because that would entail executing a separate SQL statement for each row in the table. If you want to do this nonetheless, give your model a custom method, and add that method’s name to list_display. (See below … Read more
This class Meta: ordering = [‘username’] should be ordering = [‘user__username’] if it’s in your UserProfile admin class. That’ll stop the exception, but I don’t think it helps you. Ordering the User model as you describe is quite tricky, but see http://code.djangoproject.com/ticket/6089#comment:8 for a solution.
To resolve this go to settings.py where there is new-style MIDDLEWARE (introduced in Django 1.10) Change that to old-style MIDDLEWARE_CLASSES https://docs.djangoproject.com/en/stable/topics/http/middleware/#upgrading-pre-django-1-10-style-middleware
After setting up your STATIC_ROOT and STATIC_URL, you may have to run python manage.py collectstatic
Windows has a command line utility “Run as”, which can be used as runas [{/profile | /noprofile}] [/env] [{/netonly | /savecred}] [/smartcard] [/showtrustlevels] [/trustlevel] /user:<UserAccountName> “<ProgramName> <PathToProgramFile>” for further reference https://technet.microsoft.com/en-us/library/cc771525.aspx You can use this in code like below import subprocess as sp prog = sp.Popen([‘runas’, ‘/noprofile’, ‘/user:Administrator’, ‘NeedsAdminPrivilege.exe’],stdin=sp.PIPE) prog.stdin.write(‘password’) prog.communicate()
I’ve found a different solution that seems to be platform-independent. It tries to write system-preferences. If that fails, the user might not be an admin. As Tomáš Zato suggested, you might want to suppress error messages caused by this method. You can do this by setting System.err: import java.io.OutputStream; import java.io.PrintStream; import java.util.prefs.Preferences; import static … Read more
Used request instance as temporary container for obj. Overrided Inline method formfield_for_foreignkey to modify queryset. This works at least on django 1.2.3. class RoomInline(admin.TabularInline): model = Room def formfield_for_foreignkey(self, db_field, request=None, **kwargs): field = super(RoomInline, self).formfield_for_foreignkey(db_field, request, **kwargs) if db_field.name == ‘inside_room’: if request._obj_ is not None: field.queryset = field.queryset.filter(building__exact = request._obj_) else: field.queryset = … Read more
I was also scratching my head around the same issue, and everything worked after I set the role to be root when adding the first admin user. use admin db.createUser( { user: ‘admin’, pwd: ‘password’, roles: [ { role: ‘root’, db: ‘admin’ } ] } ); exit; If you have already created the admin user, … Read more