Probably there could be better solutions, but the following should work for you: public static void main(String[] args) { Integer[] a = new Integer[] { 1, 0, 0, 1, 0, 0 }; List<Integer> a1 = Arrays.asList(a); Integer[] b = new Integer[] { 0, 1, 1, 0, 0, 0 }; List<Integer> a2 = Arrays.asList(b); List<Integer> a3 … Read more
You never enter any data into temperatures. Therefore temperatures.size() == 0 Anything divided by 0 is NaN So the code is doing exactly what you told it to.
You should read new inputs inside your loop: try { … while (true) { num = Integer.parseInt(data); myArray.add(num); } } catch (NumberFormatException e) { }; Currently you are adding the same input infinite times to your List. P.S. perhaps you shouldn’t use an infinite while loop. How do you plan to finish reading the inputs? … Read more
use return listA.equals(listB); Returns true if and only if the specified object is also a list, both lists have the same size, and all corresponding pairs of elements in the two lists are equal.
After getting value from intent: ArrayList<String> arrayList = new ArrayList<String>(); valueaddlist = (Button) findViewById(R.id.valueaddlist); valueaddlist.setOnClickListener(new OnClickListener() { public void onClick(View v){ arrayList.add(product_id); arrayList.add(product_title); arrayList.add(product_image); arrayList.add(product_price); arrayList.add(product_desc); } valuedisplaylist = (Button) findViewById(R.id.valuedisplaylist); valuedisplaylist.setOnClickListener(new OnClickListener() { public void onClick(View v){ Intent intent = new Intent(this,AddedListProducts.class); intent.putStringArrayListExtra(“arrayList”, (ArrayList<String>) arrayList); startActivity(intent); } May be this will help you. In … Read more
String[][] strings2 = convertStringArrayList(listOfStringLists); Convert ArrayList<ArrayList<String>> to String[][] method: private String[][] convertStringArrayList( ArrayList<ArrayList<String>> listOfStringLists ) { String[][] stringGroups = new String[listOfStringLists.size()][]; for ( int i=0; i< listOfStringLists.size(); i++ ) { ArrayList<String> stringArray = listOfStringLists.get(i); String[] stringsChildren = Arrays.copyOf(stringArray.toArray(), stringArray.toArray().length, String[].class); stringGroups[i] = stringsChildren; } return stringGroups; }
Find the intersection Find the union Subtract the intersection from the union Code: public static void main(String[] args) { Set<Integer> set1 = new HashSet<Integer>(Arrays.asList(1, 2, 3, 4, 5)); Set<Integer> set2 = new HashSet<Integer>(Arrays.asList(1, 3, 6, 7)); Set<Integer> intersection = new HashSet<Integer>(set1); intersection.retainAll(set2); // set1 is now the union of set1 and set2 set1.addAll(set2); // set1 … Read more
Collections.rotate will do that you want String[] daysArr = { “Mon”, “Tue”, “Wed”, “Thu”, “Fri”, “Sat” }; List<String> daysList = Arrays.asList(daysArr); String input = “Fri”; int index = daysList.indexOf(input); if (index > 0) { Collections.rotate(daysList, -index); } System.out.println(daysList); Hope it helps!
If you want that behaviour: List<T> snake = new ArrayList<>(){ @Override public T get(int i) { return super.get((i + size()) % size()); } }; This will work for any value of i.
You can compare each element of this arraylist to each element of that arraylist.if they equal you will print…you can use for each loop.