In ASP.Net MVC4 the default JavaScript serializer which is used in the JsonResult class is still the JavaScriptSerializer (you can check it in the code) I think you have confused it with the ASP.Net Web.API where JSON.Net is the default JS serializer but MVC4 doesn’t use it. So you need to configure JSON.Net to work … Read more
If you are required to pass the same properties to each page, then creating a base viewmodel that is used by all your view models would be wise. Your layout page can then take this base model. If there is logic required behind this data, then this should be put into a base controller that … Read more
I could do this with a custom attribute as follows. [AuthorizeUser(AccessLevel = “Create”)] public ActionResult CreateNewInvoice() { //… return View(); } Custom Attribute class as follows. public class AuthorizeUserAttribute : AuthorizeAttribute { // Custom property public string AccessLevel { get; set; } protected override bool AuthorizeCore(HttpContextBase httpContext) { var isAuthorized = base.AuthorizeCore(httpContext); if (!isAuthorized) { … Read more
The solution I originally posted is questionable (is a dirty hack). The tweaked behaviour has changed in Microsoft.AspNet.Web.Optimization package and the tweak does not work anymore, as pointed out by many commenters. Right now I cannot reproduce the issue at all with the version 1.1.3 of the package. Please see sources of System.Web.Optimization.BundleCollection (you can … Read more
Try //adding data to session //assuming the method below will return list of Products var products=Db.GetProducts(); //Store the products to a session Session[“products”]=products; //To get what you have stored to a session var products=Session[“products”] as List<Product>; //to clear the session value Session[“products”]=null;
The following solution will work with sql server 2005 and above. You can use output to get the required field. inplace of id you can write your key that you want to return. do it like this FOR SQL SERVER 2005 and above using(SqlCommand cmd=new SqlCommand(“INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) output INSERTED.ID VALUES(@na,@occ)”,con)) { cmd.Parameters.AddWithValue(“@na”, Mem_NA); cmd.Parameters.AddWithValue(“@occ”, … Read more
If you simply care about getting the root/base url of the site so you can append that to get the other url you are after, you may simply use / as the first character of your url. var urlToJobIndex2= “/jobs/GetIndex”; Here is an alternate approach if you want more than just the app root (Ex … Read more
Your model is null because the way you’re supplying the inputs to your form means the model binder has no way to distinguish between the elements. Right now, this code: @foreach (var planVM in Model) { @Html.Partial(“_partialView”, planVM) } is not supplying any kind of index to those items. So it would repeatedly generate HTML … Read more
You can validate individual controls using Validator.element(element) – see documentation here, so you could use the following approach (you haven’t posted the views html so can’t write the actual code for you) In the Next button click event Select all the the controls within the associated div – e.g. var controls = $(this).closest(‘div’).find(‘input, textarea, select’); … Read more
My current setup (on MVC3, but I think it still applies) relies on having an ErrorController, so I use: <system.web> <customErrors mode=”On” defaultRedirect=”~/Error”> <error redirect=”~/Error/NotFound” statusCode=”404″ /> </customErrors> </system.web> And the controller contains the following: public class ErrorController : Controller { public ViewResult Index() { return View(“Error”); } public ViewResult NotFound() { Response.StatusCode = 404; … Read more