By value. 1 But you can make it copy by ref instead: void SomeFunction(const int& value) { boost::bind(…, boost::ref(value)); boost::bind(…, boost::cref(value)); // by const ref } 1 http://www.boost.org/doc/libs/1_46_1/libs/bind/bind.html#Purpose a copy of the value of i is stored into the function object. boost::ref and boost::cref can be used to make the function object store a reference … Read more
boost::bind has overloaded relational operators, std::bind does not. boost::bind supports non-default calling conventions, std::bind is not guaranteed to (standard library implementations may offer this as an extension). boost::bind provides a direct mechanism to allow one to prevent eager evaluation of nested bind expressions (boost::protect), std::bind does not. (That said, one can use boost::protect with std::bind … Read more
boost::function allows anything with an operator() with the right signature to be bound as the parameter, and the result of your bind can be called with a parameter int, so it can be bound to function<void(int)>. This is how it works (this description applies alike for std::function): boost::bind(&klass::member, instance, 0, _1) returns an object like … Read more
Use the following instead: boost::function<void (int)> f2( boost::bind( &myclass::fun2, this, _1 ) ); This forwards the first parameter passed to the function object to the function using place-holders – you have to tell Boost.Bind how to handle the parameters. With your expression it would try to interpret it as a member function taking no arguments. … Read more