Maybe it’s not working with PNG because PNG only supports compression levels 0 to 9. I’d also rather modify the behaviour based on MIME type, not extension. And I guess you’re checking your POST user input before using it in code 😉 Here’s my variant of the code: $path = “../images/DVDs/”; $img = $path . … Read more
Take a look at the “texture from camera” activity. Note it allows you to manipulate the image in various ways, notably “zoom”. The “zoom” is done by modifying the texture coordinates. The ScaledDrawable2D class does this; the setScale() call changes the “zoom”, rather than scaling the rect itself. Texture coordinates range from 0.0 to 1.0 … Read more
This is done by only using a part of the image as the thumbnail which has a 1:1 aspect ratio (mostly the center of the image). If you look closely you can see it in the flickr thumbnail. Because you have “crop” in your question, I’m not sure if you didn’t already know this, but … Read more
Alright, I will paste the comment as answer 🙂 -> RelativeLayout rl = (RelativeLayout) findViewById(R.id.rl1); final Options bitmapOptions=new Options(); DisplayMetrics metrics = getResources().getDisplayMetrics(); bitmapOptions.inDensity = metrics.densityDpi; bitmapOptions.inTargetDensity=1; /*`final` modifier might be necessary for the Bitmap*/ Bitmap bmp= BitmapFactory.decodeResource(getResources(), R.drawable.ver_bottom_panel_tiled_long, bitmapOptions); bmp.setDensity(Bitmap.DENSITY_NONE); bmp = Bitmap.createBitmap(bmp, 0, 0, rl.getWidth(), bmp.getHeight()); Then in the code: ImageView iv = … Read more
I used this method to crop the image and it works perfect: Bitmap bmp = BitmapFactory.decodeResource(getResources(), R.drawable.xyz); Bitmap resizedBmp = Bitmap.createBitmap(bmp, 0, 0, yourwidth, yourheight); createBitmap() takes bitmap, start X, start Y, width & height as parameters.
This question is all over stackoverflow. And I’m glad it is since I had to sort this out myself recently. I’ll do my best to mark some duplicates as I go but I prefer this one since it addresses the issue with the limited image size. Short Answer The short answer is not to use … Read more
Hope This Code will help you.. Activity To Select The Image From Gallery. import java.io.File; import android.app.Activity; import android.content.Intent; import android.database.Cursor; import android.net.Uri; import android.os.Bundle; import android.provider.MediaStore; import android.util.Log; public class GalleryUtil extends Activity{ private final static int RESULT_SELECT_IMAGE = 100; public static final int MEDIA_TYPE_IMAGE = 1; private static final String TAG = “GalleryUtil”; … Read more
Use UIPrintPageRenderer from UIWebView Follow below steps : Add Category of UIPrintPageRenderer for getting PDF Data @interface UIPrintPageRenderer (PDF) – (NSData*) printToPDF; @end @implementation UIPrintPageRenderer (PDF) – (NSData*) printToPDF { NSMutableData *pdfData = [NSMutableData data]; UIGraphicsBeginPDFContextToData( pdfData, self.paperRect, nil ); [self prepareForDrawingPages: NSMakeRange(0, self.numberOfPages)]; CGRect bounds = UIGraphicsGetPDFContextBounds(); for ( int i = 0 ; … Read more
Not possible with UIImagePickerController unfortunately. The solution I recommend is to disable editing for the image picker and handle it yourself. For instance, I put the image in a scrollable, zoomable image view. On top of the image view is a fixed position “crop guide view” that draws the crop indicator the user sees. Assuming … Read more
Splitting image to tiles of MxN pixels (assuming im is numpy.ndarray): tiles = [im[x:x+M,y:y+N] for x in range(0,im.shape[0],M) for y in range(0,im.shape[1],N)] In the case you want to split the image to four pieces: M = im.shape[0]//2 N = im.shape[1]//2 tiles[0] holds the upper left tile