What is the difference between the two ways of accessing the hdf5 group in SVHN dataset?

First, there is a minor difference in output from your 2 methods. Method 1: returns the full array (of the encoded file name) Method 2: only returns the first element (character) of the array Let’s deconstruct your code to understand what you have. The first part deals with h5py data objects. f[‘digitStruct’] -> returns a … Read more

Filtering DataSet

You can use DataTable.Select: var strExpr = “CostumerID = 1 AND OrderCount > 2”; var strSort = “OrderCount DESC”; // Use the Select method to find all rows matching the filter. foundRows = ds.Table[0].Select(strExpr, strSort); Or you can use DataView: ds.Tables[0].DefaultView.RowFilter = strExpr; UPDATE I’m not sure why you want to have a DataSet returned. … Read more

Convert Dataset to XML

You can use ds.WriteXml, but that will require you to have a Stream to put the output into. If you want the output in a string, try this extension method: public static class Extensions { public static string ToXml(this DataSet ds) { using (var memoryStream = new MemoryStream()) { using (TextWriter streamWriter = new StreamWriter(memoryStream)) … Read more

Stored procedure return into DataSet in C# .Net

Try this DataSet ds = new DataSet(“TimeRanges”); using(SqlConnection conn = new SqlConnection(“ConnectionString”)) { SqlCommand sqlComm = new SqlCommand(“Procedure1”, conn); sqlComm.Parameters.AddWithValue(“@Start”, StartTime); sqlComm.Parameters.AddWithValue(“@Finish”, FinishTime); sqlComm.Parameters.AddWithValue(“@TimeRange”, TimeRange); sqlComm.CommandType = CommandType.StoredProcedure; SqlDataAdapter da = new SqlDataAdapter(); da.SelectCommand = sqlComm; da.Fill(ds); }

How to pass dynamic column names in dplyr into custom function?

Using the latest version of dplyr (>=0.7), you can use the rlang !! (bang-bang) operator. library(tidyverse) from <- “Stand1971” to <- “Stand1987” data %>% mutate(diff=(!!as.name(from))-(!!as.name(to))) You just need to convert the strings to names with as.name and then insert them into the expression. Unfortunately I seem to have to use a few more parenthesis than … Read more