You can pass the format in to the ToString method, e.g.: myFloatVariable.ToString(“0.00”); //2dp Number myFloatVariable.ToString(“n2”); // 2dp Number myFloatVariable.ToString(“c2”); // 2dp currency Standard Number Format Strings
5.55 % 1 Keep in mind this won’t help you with floating point rounding problems. I.e., you may get: 0.550000000001 Or otherwise a little off the 0.55 you are expecting.
A decimal(9,6) stores 6 digits on the right side of the comma. Whether to display trailing zeroes or not is a formatting decision, usually implemented on the client side. But since SSMS formats float without trailing zeros, you can remove trailing zeroes by casting the decimal to a float: select cast(123.4567 as DECIMAL(9,6)) , cast(cast(123.4567 … Read more
You might want to look at the DecimalFormat class; it supports different locales (eg: in some countries that would get formatted as 1.000.500.000,57 instead). You also need to convert that string into a number, this can be done with: double amount = Double.parseDouble(number); Code sample: String number = “1000500000.574”; double amount = Double.parseDouble(number); DecimalFormat formatter … Read more
You can either use: [x / 10.0 for x in range(5, 50, 15)] or use lambda / map: map(lambda x: x/10.0, range(5, 50, 15))
Try this code: String str = “a12.334tyz.78x”; str = str.replaceAll(“[^\\d.]”, “”); Now str will contain “12.334.78”.
For money, always decimal. It’s why it was created. If numbers must add up correctly or balance, use decimal. This includes any financial storage or calculations, scores, or other numbers that people might do by hand. If the exact value of numbers is not important, use double for speed. This includes graphics, physics or other … Read more
Use setRoundingMode, set the RoundingMode explicitly to handle your issue with the half-even round, then use the format pattern for your required output. Example: DecimalFormat df = new DecimalFormat(“#.####”); df.setRoundingMode(RoundingMode.CEILING); for (Number n : Arrays.asList(12, 123.12345, 0.23, 0.1, 2341234.212431324)) { Double d = n.doubleValue(); System.out.println(df.format(d)); } gives the output: 12 123.1235 0.23 0.1 2341234.2125 EDIT: … Read more
use this: echo sprintf(“%01.2f”, $start)
I’ve always pointed people towards Harald Schmidt’s online converter, along with the Wikipedia IEEE754-1985 article with its nice pictures. For those two specific values, you get (for 0.1): s eeeeeeee mmmmmmmmmmmmmmmmmmmmmmm 1/n 0 01111011 10011001100110011001101 | || || || || || +- 8388608 | || || || || |+— 2097152 | || || || || … Read more