How to print a double with two decimals in Android? [duplicate]
yourTextView.setText(String.format(“Value of a: %.2f”, a));
double
Converting a double to an int in C#
Because Convert.ToInt32 rounds: Return Value: rounded to the nearest 32-bit signed integer. If value is halfway between two whole numbers, the even number is returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6. …while the cast truncates: When you convert from a double or float value to an integral type, … Read more
Round double in two decimal places in C#?
This works: inputValue = Math.Round(inputValue, 2);
problem formatting fields in a JTable – differences between Integer and Double
how did Walter Laan says in his thread Never give up! Never surrender! EDIT: I can’t resist, but due to my poor English I dare not to commenting why, where and how is that possible, nor works correctly, for confirmations I added Rob’s two (little bit) modified class for TableColumnRendering …, import java.awt.EventQueue; import java.math.RoundingMode; … Read more
Why c# decimals can’t be initialized without the M suffix?
The type of a literal without the m suffix is double – it’s as simple as that. You can’t initialize a float that way either: float x = 10.0; // Fail The type of the literal should be made clear from the literal itself, and the type of variable it’s assigned to should be assignable … Read more
Convert double to string C++? [duplicate]
You can’t do it directly. There are a number of ways to do it: Use a std::stringstream: std::ostringstream s; s << “(” << c1 << “, ” << c2 << “)”; storedCorrect[count] = s.str() Use boost::lexical_cast: storedCorrect[count] = “(” + boost::lexical_cast<std::string>(c1) + “, ” + boost::lexical_cast<std::string>(c2) + “)”; Use std::snprintf: char buffer[256]; // make sure … Read more
How to manipulate arrays. Find the average. Beginner Java
Using an enhanced for would be even nicer: int sum = 0; for (int d : data) sum += d; Another thing that will probably give you a big surprise is the wrong result that you will obtain from double average = sum / data.length; Reason: on the right-hand side you have integer division and … Read more
Should we generally use float literals for floats instead of the simpler double literals?
Yes, you should use the f suffix. Reasons include: Performance. When you write float foo(float x) { return x*3.14; }, you force the compiler to emit code that converts x to double, then does the multiplication, then converts the result back to single. If you add the f suffix, then both conversions are eliminated. On … Read more
Adding and subtracting doubles are giving strange results [duplicate]
In Java, double values are IEEE floating point numbers. Unless they are a power of 2 (or sums of powers of 2, e.g. 1/8 + 1/4 = 3/8), they cannot be represented exactly, even if they have high precision. Some floating point operations will compound the round-off error present in these floating point numbers. In … Read more
Convert Double to Binary representation?
Long.toBinaryString(Double.doubleToRawLongBits(d)) appears to work just fine. System.out.println(“0: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(0D))); System.out.println(“1: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(1D))); System.out.println(“2: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(2D))); System.out.println(“2^900: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(Math.pow(2, 900)))); System.out.println(“Double.MAX_VALUE: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(Double.MAX_VALUE))); /* prints: 0: 0b0 1: 0b11111111110000000000000000000000000000000000000000000000000000 2: 0b100000000000000000000000000000000000000000000000000000000000000 2^900: 0b111100000110000000000000000000000000000000000000000000000000000 Double.MAX_VALUE: 0b111111111101111111111111111111111111111111111111111111111111111 */