int[] nums = {5,1,2,11,3}; //List or Vector Arrays.sort(nums); //Collections.sort() for List,Vector String a=Arrays.toString(nums); //toString the List or Vector String ar[]=a.substring(1,a.length()-1).split(“, “); System.out.println(Arrays.toString(ar)); UPDATE: A shorter version: int[] nums = {-5,1,2,11,3}; Arrays.sort(nums); String[] a=Arrays.toString(nums).split(“[\\[\\]]”)[1].split(“, “); System.out.println(Arrays.toString(a));
Use std::copy defined in the header <algorithm>. The args are a pointer to the first element of the input, a pointer to one past the last element of the input, and a pointer to the first element of the output. ( https://en.cppreference.com/w/cpp/algorithm/copy ) int * result = new int[size1 + size2]; std::copy(arr1, arr1 + size1, … Read more
“What are the differences between Integer and Int?” Integer is just an alias for java.lang.Integer. Int is the Scala integer with the extra capabilities. Looking in Predef.scala you can see this the alias: /** @deprecated use <code>java.lang.Integer</code> instead */ @deprecated type Integer = java.lang.Integer However, there is an implicit conversion from Int to java.lang.Integer if … Read more
the Integer class is provided so that values can be boxed/unboxed in a pure OO manner. use int where appropriate unless you specifically need to use it in an OO way; in which case Integer is appropriate. Java Int vs Integer However, very different things are going on under the covers here. An int is … Read more
Note that there is a difference between a cast to long and a cast to Long. If you cast to long (a primitive value) then it should be automatically boxed to a Long (the reference type that wraps it). You could alternatively use new to create an instance of Long, initializing it with the int … Read more
Use Convert.ToInt32 from mscorlib as in decimal value = 3.14m; int n = Convert.ToInt32(value); See MSDN. You can also use Decimal.ToInt32. Again, see MSDN. Finally, you can do a direct cast as in decimal value = 3.14m; int n = (int) value; which uses the explicit cast operator. See MSDN.
They are being divided in integer arithmetics. So dividing integer a by integer b you get how many times b fits into a. Also a % b will give you a remainder of a division. So (a / b ) * b + a % b = a
I experimented with solutions using lookup tables, but found them fraught with issues, and actually not very fast. The fastest solution turned out to be the least imaginitive: int fast_atoi( const char * str ) { int val = 0; while( *str ) { val = val*10 + (*str++ – ‘0’); } return val; } … Read more
This will work: let digits = [1,2,3,4] let intValue = digits.reduce(0, combine: {$0*10 + $1}) For Swift 4+ : let digits = [1,2,3,4] let intValue = digits.reduce(0, {$0*10 + $1}) Or this compiles in more versions of Swift: (Thanks to Romulo BM.) let digits = [1,2,3,4] let intValue = digits.reduce(0) { return $0*10 + $1 … Read more
There is a difference at run-time. int[] is an array of primitive int values. Integer[] is an “object” array, holding references to Integer objects. Most important practical difference: int[] cannot hold null values. But I’m still confused: does int[] store just a primitive values? If so – doesn’t it mean that primitive types can live … Read more