Files in a Jar are not files in the sense of a file on disk. They are simply a (possibly) compressed stream of bytes. Java makes it easy to extract these “resources” from Jar files through the use of the ClassLoader background = ImageIO.read(getClass().getResource(“/wood.jpeg”)); Should work… This will return a URL which ImageIO can use … Read more
I’d suggest doing it easier. I assume that the resource exists and the file is writable (this might be an issue if we’re speaking about system directories). public void WriteResourceToFile(string resourceName, string fileName) { using(var resource = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName)) { using(var file = new FileStream(fileName, FileMode.Create, FileAccess.Write)) { resource.CopyTo(file); } } }
Found it! Set the option useFirstColumnAsDomain to true with EmbeddedChartBuilder.setOption. This option appears to be undocumented. I found it by going to “Publish chart” (click on the chart, then select from the drop-down in the top right) and inspecting the JavaScript data structure in the given code. To be exact, I created a chart with … Read more
I think that your problem is in the location of the image. You shall place it in your source, and then use it like this: JButton button = new JButton(); try { Image img = ImageIO.read(getClass().getResource(“resources/water.bmp”)); button.setIcon(new ImageIcon(img)); } catch (Exception ex) { System.out.println(ex); } In this example, it is assumed that image is in … Read more
You should always use the resource manager and not read files directly to ensure globalization is taken into account. using System.Collections; using System.Globalization; using System.Resources; … /* Reference to your resources class — may be named differently in your case */ ResourceManager MyResourceClass = new ResourceManager(typeof(Resources)); ResourceSet resourceSet = MyResourceClass.ResourceManager.GetResourceSet(CultureInfo.CurrentUICulture, true, true); foreach (DictionaryEntry entry … Read more
getClass().getResource() uses the class loader to load the resource. This means that the resource must be in the classpath to be loaded. When doing it with Eclipse, everything you put in the source folder is “compiled” by Eclipse: .java files are compiled into .class files that go the the bin directory (by default) other files … Read more
Right-click the project file, select Properties. In the window that opens, go to the Resources tab, and if it has just a blue link in the middle of the tab-page, click it, to create a new resource. Then from the toolbar above the tab-page, select to add a new text file, give it a name, … Read more
Works fine for me. Check what you may have different. Example 1: (resources in src) Steps: File Structure Code package com.stackoverflow.test; import java.net.URL; import javax.swing.*; // Wild carded for brevity. // Actual code imports single classes public class Main { public static void main(String[] args) { SwingUtilities.invokeLater(new Runnable(){ public void run() { URL url = … Read more
There are a couple possibilities: use ld’s capability to turn any file into an object (Embedding binary blobs using gcc mingw): ld -r -b binary -o binary.o foo.bar # then link in binary.o use a bin2c/bin2h utility to turn any file into an array of bytes (Embed image in code, without using resource section or … Read more
If you will use the image in multiple places, then it’s worth loading the image data only once into memory and then sharing it between all Image elements. To do this, create a BitmapSource as a resource somewhere: <BitmapImage x:Key=”MyImageSource” UriSource=”../Media/Image.png” /> Then, in your code, use something like: <Image Source=”{StaticResource MyImageSource}” /> In my … Read more