You are trying to create a FileStream object for a directory (folder). Specify a file name (e.g. @”D:\test.txt”) and the error will go away. By the way, I would suggest that you use the StreamWriter constructor that takes an Encoding as its second parameter, because otherwise you might be in for an unpleasant surprise when … Read more
Unless you know something more about the file, you can’t access specific lines at random. New lines are delimited by the presence of line end characters and they can, in general, occur anywhere. Text files do not come with a map or index that would allow you to skip to the nth line. If you … Read more
No… If you look with Reflector you’ll see that in the end File.ReadLines opens a FileStream(path, FileMode.Open, FileAccess.Read, FileShare.Read, 0x1000, FileOptions.SequentialScan); So Read-only share. (it technically opens a StreamReader with the FileStream as described above) I’ll add that it seems to be child’s play to make a static method to do it: public static IEnumerable<string> … Read more
Your xml has multiple root elements, this is not allowed for valid xml. If you change it to the format, this should work. <?xml version=”1.0″?> <Users> <user></user> <user></user> </Users>
I’ve created download page which allows user to download up to 4gb (may be more) few months ago. Here is my working snippet: private void TransmitFile(string fullPath, string outFileName) { System.IO.Stream iStream = null; // Buffer to read 10K bytes in chunk: byte[] buffer = new Byte[10000]; // Length of the file: int length; // … Read more
Here’s what did the trick. $dir = dirname($_SERVER[‘DOCUMENT_ROOT’]).”/protected_content”; $filename = $_GET[‘file’]; $file = $dir.”https://stackoverflow.com/”.$filename; $extension = “mp3”; $mime_type = “audio/mpeg, audio/x-mpeg, audio/x-mpeg-3, audio/mpeg3”; if(file_exists($file)){ header(‘Content-type: {$mime_type}’); header(‘Content-length: ‘ . filesize($file)); header(‘Content-Disposition: filename=”‘ . $filename); header(‘X-Pad: avoid browser bug’); header(‘Cache-Control: no-cache’); readfile($file); }else{ header(“HTTP/1.0 404 Not Found”); }
Just call Read repeatedly with a small buffer (I tend to use something like 16K). Note that the call to Read may end up reading a smaller amount than you request. If you’re using a fixed chunk size and need the whole chunk in memory, you could just use an array of that size of … Read more
Since FileUpload.PostedFile.InputStream gives me Stream, I used the following code to convert it to byte array public static byte[] ReadFully(Stream input) { byte[] buffer = new byte[input.Length]; //byte[] buffer = new byte[16 * 1024]; using (MemoryStream ms = new MemoryStream()) { int read; while ((read = input.Read(buffer, 0, buffer.Length)) > 0) { ms.Write(buffer, 0, read); … Read more
It seems i found a soultion to the problem myself. http://www.codeplex.com/ExcelDataReader This library seems to work nicely and it takes a stream to read the excel file. ExcelDataReader reader = new ExcelDataReader(ExcelFileUpload.PostedFile.InputStream);
You need to reset the position of the stream before copying. outStream.Position = 0; outStream.CopyTo(fileStream); You used the outStream when saving the file using the imageFactory. That function populated the outStream. While populating the outStream the position is set to the end of the populated area. That is so that when you keep on writing … Read more