FizzBuzz program (details given) in Javascript [closed]
for (let i = 1; i <= 100; i++) { let out=””; if (i % 3 === 0) out += ‘Fizz’; if (i % 5 === 0) out += ‘Buzz’; console.log(out || i); }
fizzbuzz
Writing FizzBuzz
I think your implementation is unnecessarily complex. This one does the job and is easier to understand: public void DoFizzBuzz() { for (int i = 1; i <= 100; i++) { bool fizz = i % 3 == 0; bool buzz = i % 5 == 0; if (fizz && buzz) Console.WriteLine (“FizzBuzz”); else if … Read more
I am interested in a more optimized solution for sum of all fizzbuzz numbers in a given range
The fizzbuzz numbers which are less or equal to N are integers between 0 and N that are divisible by 15. Their sum is sum(15*i for i = 1 to N/15) That’s equal to 15*sum(i for i i=1 to N/15), or 15*(N/15)*(1+N/15)/2. (Note, here / means rounding down integer division). The sum of fizzbuzz numbers … Read more