Linux grep command with relevant values as output
For your case, you have one line of leading and one line of trailing context you care about, so grep -C1 Toronto input should do it.
For your case, you have one line of leading and one line of trailing context you care about, so grep -C1 Toronto input should do it.
With awk: awk ‘BEGIN{FS=”[ ,]”; OFS=”,”} {for (i=2; i<=NF; i++) print $i,$1}’ file Output: foo,ted bar,ted zoo,ted ket,john ben,john See: 8 Powerful Awk Built-in Variables – FS, OFS, RS, ORS, NR, NF, FILENAME, FNR
grep can read directly from a file, so unless you are intentionally trying to limit the input size the use of head is unnecessary. Likewise, cat is pointless here. The following should work: grep “@yahoo.com” EmailList.csv > file2.csv
With GNU grep: grep ‘[[:alpha:]]’ file or GNU sed: sed ‘/[[:alpha:]]/!d’ file Output: 0hjjAby68xp H5e
That’ll do the trick import re s=””text” “some”” res = re.subn(‘”([^”]*)”‘, ‘<em>\\1</em>’, s)[0]
In POSIX grep, -v is a matching control option to invert match. In this usage case, it is telling grep to match all lines that do NOT contain the string “:0” For more information, man grep
date -d’11/2/1998′ +%m%d%y 110298
If you can slurp whole input: perl -e’undef$/; $a=<>; print “$_\n” for $a=~m/(?:\b\S+\b\s+){5}your regexp(?:\s+\b\S+\b){5}/sg ‘ <input — 5 words of context.