http-post - w3toppers.com

How can I read the data received in application/x-www-form-urlencoded format on Node server?

If you are using Express.js as Node.js web application framework, then use ExpressJS body-parser. The sample code will be like this. var bodyParser = require(‘body-parser’); app.use(bodyParser.json()); // support json encoded bodies app.use(bodyParser.urlencoded({ extended: true })); // support encoded bodies // With body-parser configured, now create our route. We can grab POST // parameters using req.body.variable_name … Read more

How to send JSON as part of multipart POST-request

You are setting the header yourself, including a boundary. Don’t do this; requests generates a boundary for you and sets it in the header, but if you already set the header then the resulting payload and the header will not match. Just drop you headers altogether: def send_request(): payload = {“param_1”: “value_1”, “param_2”: “value_2”} files … Read more

Node.js – How to send data from html to express

Using http.createServer is very low-level and really not useful for creating web applications as-is. A good framework to use on top of it is Express, and I would seriously suggest using it. You can install it using npm install express. When you have, you can create a basic application to handle your form: var express … Read more

jQuery Ajax POSTing array to ASP.NET MVC Controller

Just set the traditional parameter to true: $.ajax({ type: “POST”, url: “/update-note-order”, dataType: “json”, traditional: true, data: { orderedIds: orderedIds, unixTimeMs: new Date().getTime() } }); Since jquery 1.4 this parameter exists because the mechanism to serialize objects into query parameters has changed.

What ‘sensitive information’ could be disclosed when setting JsonRequestBehavior to AllowGet

in your return use the following: return this.Json(“you result”, JsonRequestBehavior.AllowGet);

Fill fields in webview automatically

Thanks all for your answer, it helped me, but didn’t work. It was allways opening a white page until i found this : https://stackoverflow.com/a/25606090/3204928 So here complete solution, mixing all infos found here and there : 1) first of all you have to enable DOM storage, if you don’t do that, .GetElementByXXX will return nothing … Read more

How to use parameters with HttpPost

To set parameters to your HttpPostRequest you can use BasicNameValuePair, something like this : HttpClient httpclient; HttpPost httpPost; ArrayList<NameValuePair> postParameters; httpclient = new DefaultHttpClient(); httpPost = new HttpPost(“your login link”); postParameters = new ArrayList<NameValuePair>(); postParameters.add(new BasicNameValuePair(“param1”, “param1_value”)); postParameters.add(new BasicNameValuePair(“param2”, “param2_value”)); httpPost.setEntity(new UrlEncodedFormEntity(postParameters, “UTF-8”)); HttpResponse response = httpclient.execute(httpPost);

Having troubles calling a Controller Post Method

I had a [lot] of trouble with this and I used this in the end; View: <% using (Html.BeginForm( “PhotoAdd”, “Photos”, FormMethod.Post, new { enctype = “multipart/form-data” })) { %> <input type=”file” id=”file” name=”file” class=”field” style=”width:300px;”/> <%} %> Controller: var file = Request.Files[“file”]; byte[] buf = new byte[file.ContentLength]; file.InputStream.Read(buf, 0, file.ContentLength); I’m not sure whether … Read more

ASP.NET File Upload

1.Create Uploadfile.aspx 2.Embed the Uploadfile.aspx in Your Html page using iframe <%@ Page Language=”C#” AutoEventWireup=”true” CodeFile=”Uploadfile.aspx.cs” Inherits=”Uploadfile” %> <!DOCTYPE html PUBLIC “-//W3C//DTD XHTML 1.0 Transitional//EN” “http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd”> <html xmlns=”http://www.w3.org/1999/xhtml”> <head runat=”server”> <title>File Upload Control</title> </head> <body> <form id=”form1″ runat=”server”> <div> <asp:FileUpload runat=”server” ID=”fuSample” /> <asp:Button runat=”server” ID=”btnUpload” Text=”Upload” onclick=”btnUpload_Click” /> <asp:Label runat=”server” ID=”lblMessage” Text=””></asp:Label> </div> </form> … Read more

Getting a POST variable

Use this for GET values: Request.QueryString[“key”] And this for POST values Request.Form[“key”] Also, this will work if you don’t care whether it comes from GET or POST, or the HttpContext.Items collection: Request[“key”] Another thing to note (if you need it) is you can check the type of request by using: Request.RequestType Which will be the … Read more