Looks like you’re already using request module. in this case all you need to post multipart/form-data is to use its form feature: var req = request.post(url, function (err, resp, body) { if (err) { console.log(‘Error!’); } else { console.log(‘URL: ‘ + body); } }); var form = req.form(); form.append(‘file’, ‘<FILE_DATA>’, { filename: ‘myfile.txt’, contentType: ‘text/plain’ … Read more
The process is as follows: Create dictionary with the userName, userEmail, and userPassword parameters. NSDictionary *params = @{@”userName” : @”rob”, @”userEmail” : @”[email protected]”, @”userPassword” : @”password”}; Determine the path for the image: NSString *path = [[NSBundle mainBundle] pathForResource:@”avatar” ofType:@”png”]; Create the request: NSString *boundary = [self generateBoundaryString]; // configure the request NSMutableURLRequest *request = [[NSMutableURLRequest … Read more
You can’t POST using JSONP…it simply doesn’t work that way, it creates a <script> element to fetch data…which has to be a GET request. There’s not much you can do besides posting to your own domain as a proxy which posts to the other…but user’s not going to be able to do this directly and … Read more
The following code describes a simple example using POST method.(How one can pass data by POST method) Here, I describe how one can use of POST method. 1. Set post string with actual username and password. NSString *post = [NSString stringWithFormat:@”Username=%@&Password=%@”,@”username”,@”password”]; 2. Encode the post string using NSASCIIStringEncoding and also the post string you need … Read more
JsonObjectRequest actually accepts JSONObject as body. From this blog article, final String url = “some/url”; final JSONObject jsonBody = new JSONObject(“{\”type\”:\”example\”}”); new JsonObjectRequest(url, jsonBody, new Response.Listener<JSONObject>() { … }); Here is the source code and JavaDoc (@param jsonRequest): /** * Creates a new request. * @param method the HTTP method to use * @param url … Read more
Here’s code from my app to post an image to our web server: // Dictionary that holds post parameters. You can set your post parameters that your server accepts or programmed to accept. NSMutableDictionary* _params = [[NSMutableDictionary alloc] init]; [_params setObject:[NSString stringWithString:@”1.0″] forKey:[NSString stringWithString:@”ver”]]; [_params setObject:[NSString stringWithString:@”en”] forKey:[NSString stringWithString:@”lan”]]; [_params setObject:[NSString stringWithFormat:@”%d”, userId] forKey:[NSString stringWithString:@”userId”]]; … Read more
Update in 2018: I just got some points for this old answer, and just wanted to add that the best solution would be to make the operation idempotent so that duplicate submissions are harmless. Eg, if the form creates an order, put a unique ID in the form. The first time the server sees an … Read more
You’re passing an object, not a JSON string. When you pass an object, jQuery uses $.param to serialize the object into name-value pairs. If you pass the data as a string, it won’t be serialized: $.ajax({ type: ‘POST’, url: ‘/form/’, data: ‘{“name”:”jonas”}’, // or JSON.stringify ({name: ‘jonas’}), success: function(data) { alert(‘data: ‘ + data); }, … Read more
In Swift 3 and later you can: let url = URL(string: “http://www.thisismylink.com/postName.php”)! var request = URLRequest(url: url) request.setValue(“application/x-www-form-urlencoded”, forHTTPHeaderField: “Content-Type”) request.httpMethod = “POST” let parameters: [String: Any] = [ “id”: 13, “name”: “Jack & Jill” ] request.httpBody = parameters.percentEncoded() let task = URLSession.shared.dataTask(with: request) { data, response, error in guard let data = data, let … Read more
The @Body annotation defines a single request body. interface Foo { @POST(“/jayson”) FooResponse postJson(@Body FooRequest body); } Since Retrofit uses Gson by default, the FooRequest instances will be serialized as JSON as the sole body of the request. public class FooRequest { final String foo; final String bar; FooRequest(String foo, String bar) { this.foo = … Read more