Due to imprecise float comparison you can or your comparison with np.isclose, isclose takes a relative and absolute tolerance param so the following should work: df[‘result’] = df[‘actual_credit’].ge(df[‘min_required_credit’]) | np.isclose(df[‘actual_credit’], df[‘min_required_credit’])
No, there is no best practice. Unfortunately, there cannot be, because almost all floating-point calculations introduce some rounding error, and the consequences of the errors are different for different applications. Typically, software will perform some calculations that ideally would yield some exact mathematical result x but, due to rounding errors (or other issues), produce an … Read more