If you want an int as result, multiply with the base: int a = 5; int b = 5; int c = 10 * a + b; // 55 If you want the result to be a std::string, use std::to_string (since C++11): int a = 5; int b = 5; std::string c = std::to_string(a) + … Read more
L, U and F means long, unsigned and float respectively. so, the code means int a = (long) 200; int a = (unsigned) 200; int a = (float) 200;
The error message is pretty clear: you declared that your function would return an int, but you never did.
There are two options: casting: this will produce an unrounded result. For example: 2.7 will be converted to 2. int someInt = (int) someFloat; rounding: the result will be rounded correctly. int someInt = Math.round(someFloat);
When Answering your question, I am not the person to ask why you need regex for this. And the regex you want is /^(1[89]|[2-9][0-9]|1([0-3][0-9]|40))$/ Sample var age=/^(1[89]|[2-9][0-9]|1([0-3][0-9]|40))$/; console.log(age.test(18)); console.log(age.test(140)); console.log(age.test(12)); console.log(age.test(142)); But, you can simply use the following code to test if(age>=18 && age<=140) That is function test(age){ return age>=18 && age<=140; } console.log(test(18)); console.log(test(140)); … Read more
To avoid a float result, use integer division: // instead of /.
It seems the API you’re using scheduler.scheduleSyncRepeatingTask() expects the last two parameters to be of type long. Since, an int can implicitly fit into a long, passing timeBetween as it is will work just fine. Same goes for the second parameter too. You can pass 0 instead of 0L there as well. It works out … Read more